Let's analyze the structure of ${\mathrm{CuSO}}_4\cdot 5{\mathrm{H}}_2\mathrm{O}$ to determine the types of bonds present.

The compound exists as $\left[\mathrm{Cu}{\left({\mathrm{H}}_2\mathrm{O}\right)}_4\right]{\mathrm{SO}}_4\cdot {\mathrm{H}}_2\mathrm{O}$. This means four water molecules are coordinated to the central copper(II) ion, forming a complex cation, while one water molecule is outside the coordination sphere and is involved in hydrogen bonding.

1. Coordinate Covalent Bonds:

In the complex ion ${\left[\mathrm{Cu}{\left({\mathrm{H}}_2\mathrm{O}\right)}_4\right]}^{2+}$, each water molecule acts as a ligand, donating a lone pair of electrons from its oxygen atom to the ${\mathrm{Cu}}^{2+}$ ion. Thus, there are 4 coordinate covalent bonds between ${\mathrm{Cu}}^{2+}$ and the four water molecules.

2. Covalent Bonds:

• Each of the five water molecules has 2 O-H covalent bonds. So, $5\times 2=10$ O-H covalent bonds.
• In the sulfate ion (${\mathrm{SO}}_4^{2-}$), there are 4 S-O covalent bonds.
• Total covalent bonds = $10$ (from water) + $4$ (from sulfate) = $14$ covalent bonds.

3. Hydrogen Bonds:

The fifth water molecule, which is not coordinated to copper, is involved in hydrogen bonding. It forms hydrogen bonds with the oxygen atoms of the sulfate ion and with the coordinated water molecules. Typically, in such hydrates, this uncoordinated water molecule forms 2 hydrogen bonds.

Therefore, the ratio of coordinate covalent bonds : covalent bonds : hydrogen bonds is $4:14:2$.

Simplifying this ratio by dividing by 2, we get $2:7:1$.

Let's re-evaluate the options based on the common understanding of the structure of copper sulfate pentahydrate. Often, the question refers to the bonds within the complex and the overall structure. Let's re-examine the options and the common interpretation.

A common representation of ${\mathrm{CuSO}}_4\cdot 5{\mathrm{H}}_2\mathrm{O}$ is that 4 water molecules are coordinated to Cu, and one water molecule is hydrogen-bonded to the sulfate ion and coordinated water molecules. The sulfate ion itself has covalent bonds. The O-H bonds within water are also covalent.

Let's re-check the options against the calculated ratio of $4:14:2$ which simplifies to $2:7:1$.

Option D is $2:7:1$.

Let's consider if there's a different interpretation that leads to option C ($1:4:1$). This would imply 1 coordinate bond, 4 covalent bonds, and 1 hydrogen bond, which is incorrect for the entire molecule.

However, if the question is asking for the ratio of types of bonds, and not the total count, it's still not $1:4:1$.

Let's re-evaluate the number of bonds carefully, as this is a common point of confusion.

Structure: ${\left[\mathrm{Cu}{\left({\mathrm{H}}_2\mathrm{O}\right)}_4\right]}^{2+}{\mathrm{SO}}_4^{2-}\cdot {\mathrm{H}}_2\mathrm{O}$

Coordinate Covalent Bonds: 4 (between Cu and 4 ${\mathrm{H}}_2\mathrm{O}$ molecules).

Covalent Bonds:

• In 5 ${\mathrm{H}}_2\mathrm{O}$ molecules: $5\times 2=10$ O-H bonds.
• In ${\mathrm{SO}}_4^{2-}$ ion: 4 S-O bonds.
• Total covalent bonds = $10+4=14$.

Hydrogen Bonds: The fifth water molecule forms hydrogen bonds. It typically forms 2 hydrogen bonds (one with a coordinated water molecule and one with an oxygen of the sulfate ion). Sometimes, the number of hydrogen bonds can be interpreted differently depending on the exact crystal structure, but 2 is a common value for the uncoordinated water.

So, the ratio is $4\text{ (coordinate)}:14\text{ (covalent)}:2\text{ (hydrogen)}$.

Simplifying this ratio by dividing by 2 gives $2:7:1$.

This matches option D.

Let's consider if there's an alternative interpretation for option C ($1:4:1$). This would mean 2 coordinate, 8 covalent, 2 hydrogen bonds if we multiply by 2. This is still not matching our count.

There might be a specific convention or a simplified way of counting bonds in some contexts that leads to option C. However, based on the detailed structural analysis, option D ($2:7:1$) seems more accurate.

Let's re-examine the provided correct answer C. If C is correct, then the ratio is $1:4:1$. This would mean 1 coordinate bond, 4 covalent bonds, and 1 hydrogen bond. This is highly unlikely for the entire molecule. Perhaps the question is asking for a ratio per formula unit in a very specific way, or there's a misunderstanding of the bond types being counted.

Let's assume the question is asking for the ratio of types of bonds per formula unit in a simplified manner, or there's a specific convention being followed. If we consider the bonds within the complex ion and the sulfate ion separately, and then the hydrogen bonds.

Let's reconsider the possibility of a different interpretation for the number of covalent bonds. Sometimes, the S-O bonds in sulfate are considered to have some double